-6x^2+18x-12=0

Solution for -6x^2+18x-12=0 equation:

-6x^2+18x-12=0

a = -6; b = 18; c = -12;
Δ = b2-4ac
Δ = 182-4·(-6)·(-12)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-6}{2*-6}=\frac{-24}{-12}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+6}{2*-6}=\frac{-12}{-12}
=1
$